python怎么将整数反转输出(2)-木庄网络博客

1：正常整数方法实现，利用余数*10累加的方法完成。需要注意的是，python对整数除法采用“向下取整”机制，所以正数和负数要区别运算。

def reverse(self, x):
        """
        :type x: int
        :rtype: int
        """
        num = 0
        if x == 0:
            return 0
        if x < 0:
            x = -x
            while x != 0:
                num = num*10 + x%10
                x = x/10
            num = -num
        else:
            while x != 0:
                num = num*10 + x%10
                x = x/10
             
        if num>pow(2,31)-1 or num < pow(-2,31):
            return 0
        return num

2：整数转字符串，反转字符串，然后再转整数

def reverse(self, x):
        """
        :type x: int
        :rtype: int
        """
        plus_minus = ""
        reverse_x = ""
        if x<0:
            plus_minus = "-"
            x = -x
        for i in str(x):
            reverse_x = i + reverse_x
        reverse_x = plus_minus +reverse_x
        if int(reverse_x)>pow(2,31)-1 or int(reverse_x)<pow(-2,31):
            return 0