如何检查字符串是否是Python中的有效关键字？-木庄网络博客

本文摘自php中文网，作者藏色散人，侵删。

在编程中，关键字（keyword )是语言的“reserved word”，它向解释器传递特殊的含义。它可以是命令或参数。关键字不能在程序段中用作变量名。

Python中的关键字：Python语言还保留了一些表达特殊含义的关键字。这些知识是学习这门语言的必要部分。下面是python的关键字列表。

False, elif, lambda,
None, else, nonlocal,
True, except, not,
and, finally, or,
as, for, pass,
assert, from, raise,
break, global, return,
class, if, try,
continue, import, while,
def, in, with,
del, is, yield,

如何检查字符串是否是关键字?

Python在其语言中定义了一个内置模块“keyword”，它处理与关键字相关的某些操作。函数“iskeyword()”检查字符串是否为关键字。如果字符串是关键字，则返回true，否则返回false。

#Python code to demonstrate working of iskeyword() 
   
# importing "keyword" for keyword operations 
import keyword 
   
# initializing strings for testing 
s = "for"
s1 = "geeksforgeeks"
s2 = "elif"
s3 = "elseif"
s4 = "nikhil"
s5 = "assert"
s6 = "shambhavi"
s7 = "True"
s8 = "False"
s9 = "akshat"
s10 = "akash"
s11 = "break"
s12 = "ashty"
s13 = "lambda"
s14 = "suman"
s15 = "try"
s16 = "vaishnavi"
   
# checking which are keywords 
if keyword.iskeyword(s): 
        print ( s + " is a python keyword") 
else :  print ( s + " is not a python keyword") 
   
if keyword.iskeyword(s1): 
        print ( s1 + " is a python keyword") 
else :  print ( s1 + " is not a python keyword") 
   
if keyword.iskeyword(s2): 
        print ( s2 + " is a python keyword") 
else :  print ( s2 + " is not a python keyword") 
   
if keyword.iskeyword(s3): 
        print ( s3 + " is a python keyword") 
else :  print ( s3 + " is not a python keyword") 
   
if keyword.iskeyword(s4): 
        print ( s4 + " is a python keyword") 
else :  print ( s4 + " is not a python keyword") 
   
if keyword.iskeyword(s5): 
        print ( s5 + " is a python keyword") 
else :  print ( s5 + " is not a python keyword") 
   
if keyword.iskeyword(s6): 
        print ( s6 + " is a python keyword") 
else :  print ( s6 + " is not a python keyword") 
   
if keyword.iskeyword(s7): 
        print ( s7 + " is a python keyword") 
else :  print ( s7 + " is not a python keyword") 
   
if keyword.iskeyword(s8): 
        print ( s8 + " is a python keyword") 
else :  print ( s8 + " is not a python keyword") 
   
if keyword.iskeyword(s9): 
        print ( s9 + " is a python keyword") 
else :  print ( s9 + " is not a python keyword") 
   
if keyword.iskeyword(s10): 
        print ( s10 + " is a python keyword") 
else :  print ( s10 + " is not a python keyword") 
   
if keyword.iskeyword(s11): 
        print ( s11 + " is a python keyword") 
else :  print ( s11 + " is not a python keyword") 
   
if keyword.iskeyword(s12): 
        print ( s12 + " is a python keyword") 
else :  print ( s12 + " is not a python keyword") 
   
if keyword.iskeyword(s13): 
        print ( s13 + " is a python keyword") 
else :  print ( s13 + " is not a python keyword") 
   
if keyword.iskeyword(s14): 
        print ( s14 + " is a python keyword") 
else :  print ( s14 + " is not a python keyword") 
   
if keyword.iskeyword(s15): 
        print ( s15 + " is a python keyword") 
else :  print ( s15 + " is not a python keyword") 
   
if keyword.iskeyword(s16): 
        print ( s16 + " is a python keyword") 
else :  print ( s16 + " is not a python keyword")