Python中可迭代对象分解为单独的变量的实现方法（代码）

#将序列分解为单独的变量

m=(1,2)

x,y=m

print("x=",x)

print("y=",y)

print("*"*30)

data=["mark",18,"超级帅",(1992,5,4)]

name,age,feature,birthday=data

print("name=",name)

print("age=",age)

print("feature=",feature)

print("birthday=",birthday)

print("*"*30)

name,age,feature,(year,mon,day)=data

print("name=",name)

print("age=",age)

print("feature=",feature)

print("year=",year)

print("mon=",mon)

print("day=",day)

x= 1

y= 2

******************************

name= mark

age= 18

feature= 超级帅

birthday= (1992, 5, 4)

******************************

name= mark

age= 18

feature= 超级帅

year= 1992

mon= 5

day= 4

#将序列分解为单独的变量

mark="mark"

m,a,r,k=mark

print(m)

print(a)

print(r)

print(k)

print("*"*30)

#有时候我们想丢弃某个值，单由于变量数量必须和要分解的对象的可分解数量相同，此时我们可以使用_来表示要丢弃的值。

mark="mark"

m,a,r,_=mark

print(m)

print(a)

print(r)

#其实_还是一个变量，指示看起来舒服点

print(_)

m

a

r

k

******************************

m

a

r

k

import numpy as np

grades=list(range(10))#定义一个0-999的分数列表

print("grades:"+str(grades))

first,*middle,last=grades

print("middle:"+str(middle))

print("去掉第一个和最后一个分数后的平均值："+str(np.mean(middle)))

grades:[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

middle:[1, 2, 3, 4, 5, 6, 7, 8]

去掉第一个和最后一个分数后的平均值：4.5

record=('mark','1782980833@qq.com','18321859453','18956245389')

name,email,*phone_numbers=record

print(name)

print(email)

print(phone_numbers)

mark

1782980833@qq.com

['18321859453', '18956245389']

records=[

    ('foo',1,2),

    ('bar','hello'),

    ('foo',3,4),

]

def do_foo(x,y):

    print('foo',x,y)

def do_bar(s):

    print('bar',s)

for tag,*args in records:

    if tag=='foo':

        do_foo(*args)

    elif tag=='bar':

        do_bar(*args)

foo 1 2

bar hello

foo 3 4

line='nobody:*:-2:-2:unp user:/var/empty:/user/nim/false'

uname,*fileds,homedir,sh=line.split(':')

print(uname)

print(homedir)

print(sh)

nobody

/var/empty

/user/nim/false