Python实现的根据文件名查找数据文件功能示例

#-*- coding: UTF-8 -*-

import os

import shutil

AllFiles=[]

NameFiles=[]

def findFie(filePath):

 pathDir = os.listdir(filePath)

 for allDir in pathDir:

  # print(allDir)

  AllFiles.append(allDir)

  #pass

#filepath = 'C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\71\\71sns'

#copyfile = 'C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\71mtp'

filepath = 'C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\72\\72sns'

copyfile = 'C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\72mtp'

shutil.rmtree(copyfile)

os.mkdir(copyfile)

findFie(filepath)

def readFile():

 readFile = open('./jobname')

 i = 0

 for eachLine in readFile:

  i= i + 1

  #print(eachLine)

  NameFiles.append(eachLine.replace('\n','')) # 去掉换行符

readFile()

#字符串比较

def doTheCompare():

 for x in NameFiles:

  print(x)

  for y in AllFiles:

   if x == y :

    copyFrom = os.path.join(filepath,x)

    copyTo = os.path.join(copyfile,x)

    shutil.copyfile(copyFrom,copyTo)

   else:

    pass

    #print ("file not find under sns process,thanks .please check with wumi.")

doTheCompare()

# -*- coding:utf-8 -*-

import os

def search(path=".", name="1"):

  for item in os.listdir(path):

    item_path = os.path.join(path, item)

    if os.path.isdir(item_path):

      search(item_path, name)

    elif os.path.isfile(item_path):

      if name in item:

        print(item_path)

if __name__ == "__main__":

  search(path=r"D:\360Downloads",name="dll")