python pycurl验证basic和digest认证的方法-木庄网络博客

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这篇文章主要介绍了python pycurl验证basic和digest认证的方法，现在分享给大家，也给大家做个参考。一起过来看看吧

简介

pycurl类似于Python的urllib，但是pycurl是对libcurl的封装，速度更快。

本文使用的是pycurl 7.43.0.1版本。

Apache下配置Basic认证

生成basic密码文件

1	`htpasswd -bc passwd.basic test 123456`

开启mod_auth_basic

1	`LoadModule auth_basic_module modules/mod_auth_basic.so`

配置到具体目录

<Directory "D:/test/basic">
  AuthName "Basic Auth Dir"
  AuthType Basic
  AuthUserFile conf/passwd.basic
  require valid-user
</Directory>

重启Apache

Apache下配置Digest认证

生成Digest密码文件

1	`htdigest -c passwd.digest "Digest Encrypt" test`

开启mod_auth_digest

1	`LoadModule auth_digest_module modules/mod_auth_digest.so`

配置到具体目录

<Directory "D:/test/digest">
  AuthType Digest
  AuthName "Digest Encrypt" # 要与密码的域一致
  AuthDigestProvider file
  AuthUserFile conf/passwd.digest
  require valid-user
</Directory>

重启Apache

验证Basic认证

# -*- coding: utf-8 -*-
import pycurl
try:
  from io import BytesIO
except ImportError:
  from StringIO import StringIO as BytesIO
buffer = BytesIO()
c = pycurl.Curl()
c.setopt(c.URL, 'http://test/basic/')
c.setopt(c.WRITEDATA, buffer)
c.setopt(c.HTTPAUTH, c.HTTPAUTH_BASIC)
c.setopt(c.USERNAME, 'test')
c.setopt(c.PASSWORD, '123456')
c.perform()
print('Status: %d' % c.getinfo(c.RESPONSE_CODE))
print(buffer.getvalue())
c.close()

验证Digest认证

# -*- coding: utf-8 -*-
import pycurl
try:
  from io import BytesIO
except ImportError:
  from StringIO import StringIO as BytesIO
buffer = BytesIO()
c = pycurl.Curl()
c.setopt(c.URL, 'http://test/digest/')
c.setopt(c.WRITEDATA, buffer)
c.setopt(c.HTTPAUTH, c.HTTPAUTH_DIGEST)
c.setopt(c.USERNAME, 'test')
c.setopt(c.PASSWORD, '123456')
c.perform()
print('Status: %d' % c.getinfo(c.RESPONSE_CODE))
print(buffer.getvalue())
c.close()