javascript如何删除子节点属性

removeAttribute(name)

<script>

  window.onload = function () { //绑定页面加载完毕时的事件处理函数

    var table = document.getElementByTagName("table")[0]; //获取表格外框的引用

    var del = document.getElementById("del");

    var reset = document.getElementById("reset");

    del.onclick = function () {

      table.removeAttribute("border");

    }

    reset.onclick = function () {

      table.setAttribute("border", "2");

    }

</script>

<table width="100%" border="2">

  <tr>

    <td>数据表格</td>

  <tr>

</table>

<button id="del">删除</button><button id="reset">恢复</button>

<script>

  function hasClass (element, className) { //类名检测函数

    var reg = new RegExp ('(\\s|^)' + className + '(\\s|$)');

    return reg.test (element, className); //使用正则检测是否有相同的样式

  }

  function deleteClass (element, className) {

    if (hasClass (element, className)) {

      element.className.replace (reg, ' '); //捕获要删除样式，然后替换为空白字符串

    }

  }

</script>

<p id="red" class="red blue bold">盒子</p>

<script>

  var red = document.getElementById ("red");

  deleteClass (red, 'blue');

</script>

document.getElementById('riskTypePie').removeAttribute("style");

var node=document.getElementById('chartWrap');

var attr=n.getAttributeNode('style');

node.removeAttributeNode(attr);