python学习日记（1）-木庄网络博客

本文摘自php中文网，作者巴扎黑，侵删。

之前学习了Alex的python教程Alex的教学真的非常棒，也很幽默。嘿嘿。希望自己可以坚持下去。

把之前学的基础知识整理回顾了一下。希望自己可以在学习python的路上越走越远，大家互勉奥。

第一周复习总结
1 初始游戏代码
number_of_kids =8
guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids:
print("You got it!")
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")

猜三次猜三次没猜中就退出则要使用到循环

（ while初相识

代码1：

count = 0
while True:
print("count:",count)
count = count +1 #count +=1
无线循环-----运用到上面的猜数字游戏）

想要在某个地方停止要如何设置?

简单举例while
count = 0
while True:
print("count:",count)
count = count *2 #count*=2
if count == 1000:
break

问：该如何加？使初始游戏能循环猜测？

改进2

number_of_kids =8

while True:
guess_number=int(input("guess_number_of_kids:"))

if guess_number==number_of_kids:
print("You got it!")
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")

问题：为什么while true 要放在这个位置？
答：while true 代表无限循环，不中断。若while true 放在下面一行的下面的话，
会无法循环下一个input，即会中断游戏。

运行结果：可无限次输入数字猜测无限循环
缺点：当输入正确答案时仍然继续猜测，没有结束。

问：改进如何在猜对的时候直接结束程序

改进3：

number_of_kids =8

while True:
guess_number=int(input("guess_number_of_kids:"))

if guess_number==number_of_kids:
print("You got it!")
break
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")

break的添加可以使得在猜对数字的时候结束游戏。但若猜不对如何是之在
指定次数内结束游戏？

改进4：

number_of_kids =8

count = 0

while True:

if count ==3:
break

guess_number=int(input("guess_number_of_kids:"))

if guess_number==number_of_kids:
print("You got it!")
break
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")

加了 if count ==3:break 后，还是没有在第三次猜测的时候成功。
原因：没有加计数！

number_of_kids =8

count = 0

while True:

if count ==3:
break

guess_number=int(input("guess_number_of_kids:"))

if guess_number==number_of_kids:
print("You got it!")
break
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")

count+=1

非常棒！

是否可以优化？

问：有什么可以代替 if count ==3: break 以及计数？

number_of_kids =8

count = 0

是否还可以优化？

有什么可以代替 if count ==3: break
while True:

if count <3:

guess_number=int(input("guess_number_of_kids:"))

if guess_number==number_of_kids:
print("You got it!")
break
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")

count+=1

print("you have tried too many times..fuck off")

只有在第三次还没有猜对的情况下进行fuckoff
进行以下修改：

number_of_kids =8

count = 0

while count <3:

guess_number=int(input("guess_number_of_kids:"))

if guess_number==number_of_kids:
print("You got it!")
break
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")

count+=1

if count ==3:

print("you have tried too many times..fuck off")

改进：高级一点哈哈哈哈

number_of_kids =8

count = 0

while count <3:

guess_number=int(input("guess_number_of_kids:"))

if guess_number==number_of_kids:
print("You got it!")
break
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")

count+=1

else:
print("you have tried too many times..fuck off")

小傻作业： 4/9 周日

如何变动代码，使得第三次出来的时候只显示数字，不显示fuckoff，等第四次输入的时候，不提示大小，反而直接输出fuckoff？

首先，理清上一段代码的思路：count从0开始运行进入while循环，但凡在小于3的范围内只要猜对就break。
没猜对就出现smaller or bigger。当count+=1等于2时，即进入第三次循环，再一次猜错时
出现bigger or smaller 后走下一个程序，即count+=1等于3，进入else运行，后面紧跟fuckoff。

作业改动思路：要使的第三次出来的时候只显示数字和小了大了提示，不显示fuckoff，则说明当count+=1等于3时，
不直接走fuckoff的程序，则说明fuckoff的设置不能出现在前面while count <3 的子程序中，而是应该并列程序，
当count=3时，继续出现猜数字的界面，后不管猜错猜对都fuckoff，并且结束。

number_of_kids =8

count = 0

while True:

if count <3:
guess_number =int(input("guess_number_of_kids:"))

if guess_number==number_of_kids:
print("You got it!")
break
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")

count+=1

if count ==3:
guess_number =int(input("guess_number_of_kids:"))
print("you have tried too many times..fuck off")
break

while优化课

如何用for来代替 while

number_of_kids =8

count = 0

while count <3: #for i in range（3）

guess_number=int(input("guess_number_of_kids:"))

if guess_number==number_of_kids:
print("You got it!")
break
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")

count+=1

else:
print("you have tried too many times..fuck off")

改成：

number_of_kids =8

count = 0

#for i in range（3）

guess_number=int(input("guess_number_of_kids:"))

if guess_number==number_of_kids:
print("You got it!")
break
elif guess_number>number_of_kids:
print("think smaller...")
else:
print("think bigger...")

count+=1

else:
print("you have tried too many times..fuck off")

最基本的for循环。

for i in range(0,10,1): #1是默认值，可以不写，不写即代表1.
print("loop",i)

for i in range(0,10,2):
print("loop",i)
运行结果：
=== RESTART: C:/Users/dell/AppData/Local/Programs/Python/Python35-32/12.py ===
loop 0
loop 2
loop 4
loop 6
loop 8
>>>

for i in range(0,10,3):
print("loop",i)
运行结果：
=== RESTART: C:/Users/dell/AppData/Local/Programs/Python/Python35-32/12.py ===
=== RESTART: C:/Users/dell/AppData/Local/Programs/Python/Python35-32/12.py ===
loop 0
loop 3
loop 6
loop 9
>>>

再次优化猜数字游戏：猜三次就退出貌似很决绝，是不是可以根据个性化需求设置提示？
加：问还要不要玩？

number_of_kids=8

count=0

while count <3:
guess_number = int(input("guess_number_of_kids:"))
if guess_number == number_of_kids:
print("yep,you got it!")
break
elif guess_number> number_of_kids:
print("think smaller...")
else:
print("think bigger...")

count+=1
if count==3:
countine_confirm = input("do you want keeping guessing...?")
if countine_confirm !="n": 若是按下n则表示退出游戏
count =0 当按下回车键后表明还想玩，则程序继续执行。

task：单独打出这段代码，理清思路。

新知识点： continue

for i in range(0,10):
if i<3:
print("loop",i)
else:
continue
print("hehe"..)

执行结果：=== RESTART: C:/Users/dell/AppData/Local/Programs/Python/Python35-32/4.py ===
loop 0
hehe...
loop 1
hehe...
loop 2
hehe...

后来加断点？？？啥意思？
for i in range(0,10):
if i<3:
print("loop",i)
else:
continue(作用是跳出本次循环，进入下一次循环）
print("hehe"..)
问：同样代码却没有hehe？

新知识点：双循环

for i in range(10):
print("________",i)
for j in range(10):
print(j)

执行结果：
=== RESTART: C:/Users/dell/AppData/Local/Programs/Python/Python35-32/4.py ===
________ 0

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